Question

The lower end of a capillary tube is immersed in mercury. The level of mercury in the tube is found to be $2$cm below the outer level. If the same tube is immersed in water, up to what height will the water rise in the capillary?

Answer 1

$h_{Hg}=\frac{{2T}_{Hg}cos{\theta }_{Hg}}{r{\rho }_{Hg}g}$

$h_{\omega }=\frac{{2T}_{\omega }cos{\theta }_{\omega }}{r\rho \omega g}$

$\frac{h_{\omega }}{h_{Hg}}=\frac{T_{\omega }}{T_{Hg}}\times \frac{{\rho }_{Hg}}{{\rho }_{\omega }}=\frac{{cos\theta }_{Hg}}{{cos\theta }_{\omega }}$