Question

The lowest number which leaves 4 as a remainder when divided by 10, 50 and 15 is

Answer 1

Let's find LCM of $10,50,$ and $15$ first.


LCM $=2\times 3\times 5\times 5=150$
Clearly, $150$ is completely divisible by $10,50,$ and $15$.
But, we want the remainder to be $4$. So, we will add $4$ to $150$.
i.e $150+4=154$.
$\therefore 154$ is the required number.