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Question

The luminous efficiency of a lamp is 5 lm W1 and its luminous intensity is 30 candela. The power of the lamp will be

A
6π W
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B
12π W
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C
24π W
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D
48π W
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Solution

The correct option is C 24π W
Luminous flux=luminous intensity4π
F = 304πlm

Luminous efficiency = 5lm/W

Power = F/Power
= 304π/5=24π

Answer. C) 24πW

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