The magnetic field at the origin due to a current element i-d-l- placed at a position r- is

The correct options are B μ_0i4πr⃗×d⃗l⃗r^3 C μ_0i4πd⃗l⃗×r⃗r^3 B= μ_04πid⃗l⃗× nbsp; r⃗r^3= μ_04πir⃗× nbsp; d⃗l⃗r^3 since d⃗l⃗× nbsp; ...

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Towards Biot-Savart Law

The magnetic ...

Question

The magnetic field at the origin due to a current element $i . \to d l$ placed at a position $\to r$ is

\frac{μ_{0} i}{4 π} \frac{\to d l \times \to r}{r^{3}}

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\frac{μ_{0} i}{4 π} \frac{\to r \times \to d l}{r^{3}}

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- \frac{μ_{0} i}{4 π} \frac{\to r \times \to d l}{r^{3}}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

- \frac{μ_{0} i}{4 π} \frac{\to d l \times \to r}{r^{3}}

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Similar questions

\to d B

\to r

\to d l

\to d B

\to r

\to d l

i d \vec{l}

\vec{r}

\frac{μ_{0} i}{4 π} \frac{d \vec{l} \times \vec{r}}{r^{3}}

- \frac{μ_{0} i}{4 π} \frac{\vec{r} \times d \vec{l}}{r^{3}}

\frac{μ_{0} i}{4 π} \frac{\vec{r} \times d \vec{l}}{r^{3}}

- \frac{μ_{0} i}{4 π} \frac{d \vec{l} \times \vec{r}}{r^{3}}

\to a, \to b

\to c

\to p, \to q

\to r

\to p = \frac{\to b \times \to c}{[\to a \to b \to c]}, \to q = \frac{\to c \times \to a}{[\to a \to b \to c]}, \to r = \frac{\to a \times \to b}{[\to a \to b \to c]}

(\to a + \to b) \cdot \to p + (\to b + \to c) \cdot \to q + (\to c + \to a) \cdot \to r =

d \to B = \frac{μ_{0}}{4 π} \frac{i (d - -- \to l \times \to r)}{{a * r}^{3}}

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