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Question

The magnetic flux through each turn of a coil having 200 turns is given as $$(t^2 - 2t) \times 10^{-3} Wb$$, where t is in second. The emf induced in the coil at t = 3 s is


A
0.7 V
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B
1.2 V
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C
0.8 V
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D
0.9 V
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Solution

The correct option is C 0.8 V
According to Faraday's law , the induced emf in a coil (having N turns) is the rate of change of magnetic flux linked with coil ,
               $$e=N\frac{d\phi_{B}}{dt}$$
given -     $$\phi_{B}=(t^{2}-2t)\times10^{-3}$$
or            $$\frac{d\phi_{B}}{dt}=(2t-2)\times10^{-3}$$
Therefore , induced emf in coil , having turns $$N=200$$ , 
               $$e=200(2t-2)\times10^{-3}$$
at $$t=3s$$ 
               $$e=200(2\times3-2)\times10^{-3}=0.8V$$    

Physics

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