Question

The magnetic force is acting on a charged particle of charge $-2\mu C$ in a magnetic field of $2$ $T$ which is in $y$ direction. When the particle velocity is$\left(2\hat{i}+3\hat{j}\right)\times {10}^{6}m/s$, then the force acting on the particle will be

• A. $4$ $N$in $z$ direction
• B. $8$ $N$in $y$ direction
• C. $8$ $N$in $z$ direction
• D. $8$ $N$ in $-z$ direction

Answer 1

The correct option is D $8$ $N$ in $-z$ direction


Lorentz force=
$q(\overrightarrow{v}\times \overrightarrow{B})=(-2\times {10}^{-6})\left((2\hat{i}+3\hat{j})\times {10}^6\times 2\hat{j}\right]=-8\hat{k}.=8Nin-z\mathrm{direction}.$