Question

The magnetic moment of ${\left[Ni{X}_4\right]}^{2-}$ ion is found to be zero. Then the metal of the complex ion is ( $X=$ monodentate anionic ligand ).

• A. $s{p}^3$ hybridised
• B. $sp{d}^2$ hybridised
• C. $ds{p}^2$ hybridised
• D. $d^{2}sp$ hybridised

Answer 1

The correct option is C $ds{p}^2$ hybridised

${\left[Ni{X}_4\right]}^{2-}$
$N{i}^{+2},d^8$ configuration but as magnetic moment is zero so pairing happens and $ds{p}^2$ hybridization.