The magnetic moment of magnet of mass 75 gm is 9 - 10-7 Am2- If the density of the material of magnet is 7-5 - 103 kg m-3 then the intensity of magnetisation will be

Magnetisation, I= MV= M(md)= Mdm Substituting the data given in the question, I=9 × 10^ 7× 7.5 × 10^375 × 10^ 3 ⇒ I=9 × 10^ 2=0.09 A/m Hence, opton (c) is t ...

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Standard XII

Physics

Exploiting Ampere's Law - Long Wire

The magnetic ...

Question

The magnetic moment of magnet of mass $75 gm$ is $9 \times 10^{- 7} {Am}^{2}$ . If the density of the material of magnet is $7.5 \times 10^{3} {kg m}^{- 3}$ then the intensity of magnetisation will be

90 A/m

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9 A/m

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0.09 A/m

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0.9 A/m

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Solution

The correct option is C $0.09 A/m$
Magnetisation, $I = \frac{M}{V} = \frac{M}{(\frac{m}{d})} = \frac{M d}{m}$

Substituting the data given in the question,

$I = \frac{9 \times 10^{- 7} \times 7.5 \times 10^{3}}{75 \times 10^{- 3}}$

$\Rightarrow I = 9 \times 10^{- 2} = 0.09 A/m$

Hence, opton (c) is the correct answer.

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The magnetic moment of magnet of mass 75 gm is 9×10−7 Am2. If the density of the material of magnet is 7.5×103 kg m−3 then the intensity of magnetisation will be

The correct option is C 0.09 A/mMagnetisation, I=MV=M(md)=Mdm Substituting the data given in the question, I=9×10−7×7.5×10375×10−3 ⇒I=9×10−2=0.09 A/m Hence, opton (c) is the correct answer.

The magnetic moment of magnet of mass $75 gm$ is $9 \times 10^{- 7} {Am}^{2}$ . If the density of the material of magnet is $7.5 \times 10^{3} {kg m}^{- 3}$ then the intensity of magnetisation will be