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Electric Generator

The magnetic ...

Question

The magnetic moment of the loop shown in the figure is (Length of each side is $a$ and current flowing in the loop is $i$ )

$- 3 a^{2} i^j$

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$- 2 a^{2} i^k$

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$- 2 a^{2} i^j$

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$- 2 a^{2} i^i$

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Solution

The correct option is A
$- 3 a^{2} i^j$

The given figure can be divided into different loops and magnetic moment is calculated for seperate loops.

(1) $M_{1} = - a^{2} i^j$

(2) $M_{2} = - a^{2} i^i$

(3) $M_{3} = - a^{2} i^j$

(4) $M_{4} = + a^{2} i^i$

(5) $M_{5} = - a^{2} i^j$

So the net magnetic moment will be:
$M_{n e t} = M_{1} + M_{2} + M_{3} + M_{4} + M_{5}$
$M_{n e t} = - 3 a^{2}^j$

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The magnetic moment of the loop shown in the figure is (Length of each side is a and current flowing in the loop is i)

The correct option is A −3a2i ^j The given figure can be divided into different loops and magnetic moment is calculated for seperate loops. (1) M1=−a2i ^j (2) M2=−a2i ^i (3) M3=−a2i ^j (4) M4=+a2i ^i (5) M5=−a2i ^j So the net magnetic moment will be: Mnet=M1+M2+M3+M4+M5 Mnet=−3a2^j

The magnetic moment of the loop shown in the figure is (Length of each side is $a$ and current flowing in the loop is $i$ )