Question

The magnetic potential energy stored in certain inductor is $80mJ$. When the current is $100mA$, then the inductance of given inductor will be

• A. $2H$
• B. $0.4H$
• C. $16H$
• D. $40H$

Answer 1

The correct option is C $16H$

Magnetic potential energystored in inductor $\left(U\right)$ = $\frac{1}{2}L{I}^{2}80\times {10}^{-3}=\frac{1}{2}\times L\times (100\times {10}^{-3}{)}^{2}L=\frac{2\times 80\times {10}^{-3}}{100\times 100\times {10}^{-6}}=\frac{160\times {10}^{-3}\times {10}^6}{{10}^4}L=16H$