The magnetic susceptibility of a rod is 499. The absolute permeability of vacuum is 4π×10−7H/m. The absolute permeability of the material of the rod is
A
π×10−4H/m
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B
2π×10−4H/m
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C
3π×10−4H/m
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D
4π×10−4H/m
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Solution
The correct option is A2π×10−4H/m χ=499 μ=μrμ0 μr=χ+1 μr=500 μ=4π×10−7×500 =2π×10−4 H/m