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Principle of Superposition

The magnitude...

Question

The magnitude of electric field intensity E, such that an electron placed in it would experience an electrical force equal to its weight, is given by:

A

m g e

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B

\frac{m g}{e}

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C

\frac{e}{m g}

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D

\frac{e^{2}}{m^{2}} g

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Solution

The correct option is B $\frac{m g}{e}$
Force on electron
$| F | = q E = e E = m g$
$E = \frac{m g}{e}$

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