Question

The magnitude of the force between a pair of conductors, each of length 110 cm, carrying a current of 10 A and separated by a distance of 10 cm is

• A. $55\times {10}^{-5}N$
• B. $44\times {10}^{-5}N$
• C. $33\times {10}^{-5}N$
• D. $22\times {10}^{-5}N$

Answer 1

The correct option is D $22\times {10}^{-5}N$

$\begin{array}{c}B=\frac{{\mu }_{o}i}{2\pi r}\\ F=\frac{{\mu }_{o}i}{2\pi r}\times iL\\ =\frac{4\pi \times {10}^{-7}\times 10\times 10\times 110}{2\pi .10}\\ =22\times {10}^{-5}\\ =2.2\times {10}^{-4}N\\ Hence,\\ optionDiscorrectanswer.\end{array}$