The magnitude of the impulse developed by a mass of $0.2 k g$ which charged its velocity from $- 4^i - 3^j + 7^k m / s$ to $2^i + 3^j +^k m / s$ is

2.07 N s e c

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1.8 N s e c

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.9 N s e c

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3.6 N s e c

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $2.07 N s e c$
Suppose the man approaches the engine with velocity $V_{o}$ & car goes back with velocity then the speed of man w.r.t earth will be $v_{o} - v$
Center of mass should not move as No enternal fore
So, $m_{1} v_{1} + m_{2} v_{2} = 0$
as $- M v + m (v_{o} - v) = 0$
$- v e$ because more in opposite direction to that of the man
$\Rightarrow - m v + 9 m v_{o} - m v = 0$
$\Rightarrow V_{o} = \frac{V (m + M)}{m}$

Suggest Corrections

Similar questions

0.2

5^i + 3^j + 7^k

2^i + 3^j +^k

(4^i +^j - 2^k) N

(2^i + 3^j -^k) m/s

2 kg

2^i + 3^j + 4^k m/s

4^i + 2^j N-s

2 kg

2^i + 3^j + 4^k m/s

4^i + 2^j N-s

(2^i +^k) m

(4^i + 3^j -^k) m

(3^i +^j) N

Join BYJU'S Learning Program