The correct option is
A ![](https://df0b18phdhzpx.cloudfront.net/ckeditor_assets/pictures/1096316/original_op1.JPG)
For the following reaction:
Halogenation reaction with Bromine is highly selective, it will abstract that hydrogen which forms the most stable free radical.
Order of stability of free radical is :
1∘<2∘<3∘
When Hydrogen (a) is abstracted,
3∘ free radical is obtained.
When Hydrogen (b) is abstracted,
2∘ free radical is obtained.
When Hydrogen (c) is abstracted,
1∘ free radical is obtained.
When Hydrogen (d) is abstracted,
2∘ free radical is obtained.
So, Hydrogen (a) will be abstracted most readily forming the given major product
![](https://df0b18phdhzpx.cloudfront.net/ckeditor_assets/pictures/1043412/original_awd.JPG)