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B
CH3CH=C=CHCH2CH3
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C
CH2=CHCH2CH=CHCH3
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D
CH2=CHCH=CHCH2CH3
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Solution
The correct option is ACH3CH=CH−CH=CHCH3 Conjugated alkene in which double bonds are more substituted is the major product. When dibromoalkane is heated with CH3OH/KOH, it undergoes dehydrohalogentation. Two molecules of HBr are eliminated to form alkadiene.