The major product of the following reaction when heated is:

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Both products are nearly in equal proportions

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None of the above

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Solution

The correct option is A

Given a choice, hydrogen is abstracted instead of deuterium because the $C - H$ bond is weaker.
For E2, we need carbon-hydrogen and the carbon-bromine bonds to be anti-periplanar.
They should be coplanar but the $C - B r$ and $C - H$ bonds should be on opposite sides.

After rotation, the antiperiplanar structure is in place for E2 (major product is):

For the minor product (only 17% yield), $D B r$ is eliminated as:

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Similar questions

The major product of the following reaction when heated is:

(C H_{3})_{2} C H C H_{2} N (C H_{2} C H_{3})_{2} C H_{3} I \to A g_{2} O \to H_{2} O h e a t \to

Z n S (s) + O_{2} (g) h e a t - - \to

The major products of the following reaction

$Z n S (s) + O_{2} (g) h e a t - --- \to$

Are

C_{2} H_{5} O N a

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