The marks obtained by a student are as follows: $67, 53, 21, 68, 90$ and $43$ . While calculating the average it was found that the average had decreased by $2$ and that $53$ had been misread. What is the correct reading?

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Solution

Misread Average $= \frac{67 + 53 + 21 + 68 + 90 + 43}{6} = 57$

Actual Average $= \frac{67 + 21 + 68 + 90 + 43 + x}{6} = 55$
$= \frac{289 + x}{6} = 55$
$x = 41$ correct reading.

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The marks obtained by a student are as follows: 67,53,21,68,90 and 43. While calculating the average it was found that the average had decreased by 2 and that 53 had been misread. What is the correct reading?

Misread Average =67+53+21+68+90+436=57 Actual Average =67+21+68+90+43+x6=55 =289+x6=55 x=41 correct reading.

The marks obtained by a student are as follows: $67, 53, 21, 68, 90$ and $43$ . While calculating the average it was found that the average had decreased by $2$ and that $53$ had been misread. What is the correct reading?

Misread Average $= \frac{67 + 53 + 21 + 68 + 90 + 43}{6} = 57$

Actual Average $= \frac{67 + 21 + 68 + 90 + 43 + x}{6} = 55$
$= \frac{289 + x}{6} = 55$
$x = 41$ correct reading.