The mass defect of nuclear reaction - 4Be10- 5B10-e-is-

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Mass Energy Equivalence

The mass defe...

Question

The mass defect of nuclear reaction : $_{4} B e^{10} \to_{5} B^{10} + e^{-}$ is:

Δ m =

At. mass of

_{4} B e^{10} -

At.mass of

_{5} B^{10}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Δ m =

At. mass of

_{4} B e^{10} -

At.mass of

_{5} B^{10} -

mass of one electron

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Δ m =

At. mass of

_{4} B e^{10} -

At.mass of

_{5} B^{10} +

mass of one electron

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Δ m =

At. mass of

_{4} B e^{10} -

At.mass of

_{5} B^{10} +

mass of two electron

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $Δ m =$ At. mass of $_{4} B e^{10} -$ At.mass of $_{5} B^{10}$
The electron has negligible mass.
Hence, the mass defect for the reaction is equal to the difference in the atomic mass of $_{4} B e^{10} -$ and the atomic mass of $_{5} B^{10}$ .

Suggest Corrections

Similar questions

Mass defect ( $Δ m$ ) is given by?

Q. The percentage of two stable boron isotopes

_{5} B^{11}

and

_{5} B^{10}

is, given that average atomic mass of boron is 10.81amu.

Q. Atomic weight of boron is

10.81

and it has two isotopes

_{5} B^{10}

and

_{5} B^{11}

. Then ratio of

_{5} B^{10} :_{5} B^{11}

in nature would be

A nucleus of mass $M + △ m$ is at rest and decays into two daughter nuclei of equal mass $\frac{M}{2}$ each. The speed of light is $c$ . The speed of daughter nuclei is

Q. A nucleus of mass

M + △ m

is at rest and decays into two daughter nuclei of equal mass

\frac{M}{2}

each. Speed of light is

c

.
The speed of daughter nuclei is
[AIEEE-2010]

Join BYJU'S Learning Program

The mass defect of nuclear reaction : 4Be10→5B10+e−is:

The correct option is A Δm=At. mass of 4Be10−At.mass of 5B10The electron has negligible mass.Hence, the mass defect for the reaction is equal to the difference in the atomic mass of 4Be10− and the atomic mass of 5B10.

The mass defect of nuclear reaction : $_{4} B e^{10} \to_{5} B^{10} + e^{-}$ is:

The correct option is A $Δ m =$ At. mass of $_{4} B e^{10} -$ At.mass of $_{5} B^{10}$
The electron has negligible mass.
Hence, the mass defect for the reaction is equal to the difference in the atomic mass of $_{4} B e^{10} -$ and the atomic mass of $_{5} B^{10}$ .