The mass of $5.6 d m^{3}$ of a certain gas at STP is $12.0 g$ . Calculate the relative molecular mass of the gas?

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Solution

Volume of the gas at STP = $5.6$ $d m^{3}$ = $5.6$ $l$ .
Mass of the gas = $12$ g.
Volume at STP = $\frac{M a s s}{M o l e c u l a r w e i g h t} \times 22.4$
$∴$ Mol. wt. = $\frac{12}{5.6} \times 22.4$ = $48$ g.

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The mass of 5.6 dm3 of a certain gas at STP is 12.0 g. Calculate the relative molecular mass of the gas?

Volume of the gas at STP = 5.6 dm3 = 5.6 l.Mass of the gas = 12g.Volume at STP = MassMolecularweight×22.4∴ Mol. wt. = 125.6×22.4 = 48g.

The mass of $5.6 d m^{3}$ of a certain gas at STP is $12.0 g$ . Calculate the relative molecular mass of the gas?

Volume of the gas at STP = $5.6$ $d m^{3}$ = $5.6$ $l$ .
Mass of the gas = $12$ g.
Volume at STP = $\frac{M a s s}{M o l e c u l a r w e i g h t} \times 22.4$
$∴$ Mol. wt. = $\frac{12}{5.6} \times 22.4$ = $48$ g.