Question

The mass of a ${}_3^{7}Li$ nucleus is $0.042u$ less than the sum of the masses of all its nucleons. What is the binding energy per nucleon of ${}_3^{7}Li$ nucleus ?

• A. $23MeV$
• B. $46MeV$
• C. $5.6MeV$
• D. $3.9MeV$

Answer 1

The correct option is C $5.6MeV$

As, $1u\equiv 931MeV$

So, Binding energy of ${}_3^{7}Li$ is $0.042\times 931=39.102MeV$

Binding energy per nucleon is $39.102/7=5.59\approx 5.6MeV$