The mass of a body indicated by a weighing machine in a lift at rest is found to be $m$ . If the lift is going up with an acceleration $a$ , then the new reading shown by the scale will be

m (1 - \frac{a}{g})

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m (1 + \frac{a}{g})

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Solution

The correct option is B $m (1 + \frac{a}{g})$
When lift is moving up
Net Normal reaction is
$N = m (g + a)$
mass measured $= \frac{N}{g} = \frac{m (g + a)}{g}$
$= m (1 + \frac{a}{g})$

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The mass of a body indicated by a weighing machine in a lift at rest is found to be m. If the lift is going up with an acceleration a, then the new reading shown by the scale will be

The correct option is B m(1+ag)When lift is moving up Net Normal reaction is N=m(g+a) mass measured =Ng=m(g+a)g =m(1+ag)

The mass of a body indicated by a weighing machine in a lift at rest is found to be $m$ . If the lift is going up with an acceleration $a$ , then the new reading shown by the scale will be

The correct option is B $m (1 + \frac{a}{g})$
When lift is moving up
Net Normal reaction is
$N = m (g + a)$
mass measured $= \frac{N}{g} = \frac{m (g + a)}{g}$
$= m (1 + \frac{a}{g})$