The mass of a particle is 10−10 g and its radius is 2×10−4cm.If its velocity is 10−6cms−1 with 0.0001% uncertainity in measurement, the uncertainity in its position is:
A
5.2×10−8m
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B
5.2×10−7m
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C
5.2×10−6m
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D
5.2×10−9m
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Solution
The correct option is A5.2×10−8m m=10−10g=10−13kgΔv=0.0001100×10−6×10−2=10−14m/s=Δx.Δp=h4πΔx=h4πΔp=h4πmΔvBy subtituting the values we get,=6.62×10−344×3.14×10−13×10−14Δx=5.2×10−8m