Question

Uncertainity in position of a minute particle of mass 25g in space is ${10}^{-5}$ m. What is the uncertainity in its velocity (in m$s^{-1}$) ? (h= 6.6 $\times$ ${10}^{-34}$ Js)

• A. 2.1x10^-34
• B. 0.5x10^-34
• C. 2.1x10^-28
• D. 0.5x10^-23

Answer 1

The correct option is C

2.1x10^-28

$△v$ = $\frac{h}{4\pi m△x}$

= $\frac{6.625\times {10}^{-34}}{4\times 3.14\times 25\times {10}^{-3}\times {10}^{-5}}$

= 2.1 $\times$ ${10}^{-28}$