The mass of a planet is 6 - 1024 kg and its diameter is 12-8 - 103 km- If the value of gravitational constant be 6-7 - 10-11 Nm2-kg2- calculate the value of acceleration due to gravity on the surface of the planet- What planet could this be -

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Acceleration Due to Gravity

The mass of a...

Question

The mass of a planet is $6 \times 10^{24}$ kg and its diameter is $12.8 \times 10^{3}$ km. If the value of gravitational constant be $6.7 \times 10^{- 11} N m^{2} / k g^{2}$ , calculate the value of acceleration due to gravity on the surface of the planet. What planet could this be ?

Open in App

Solution

Acceleration due to gravity,
$g equals fraction numerator G M over denominator R squared end fraction m a s s comma M equals 6 cross times 10 to the power of 24 K g D i a m e t e r equals 12.8 cross times 10 to the power of 6 m R a d i u s equals 6.4 cross times 10 to the power of 6 m g r a v i t a t i o n a l space c o n s tan t space G equals 6.7 cross times 10 to the power of negative 11 end exponent bevelled fraction numerator N m squared over denominator k g squared end fraction g equals fraction numerator 6.7 cross times 10 to the power of negative 11 end exponent cross times 6 cross times 10 to the power of 24 over denominator open parentheses 6.4 cross times 10 to the power of 6 close parentheses squared end fraction g equals fraction numerator 6.7 cross times 60 over denominator 6.4 cross times 6.4 end fraction g equals 9.8 space bevelled m over s squared a s space t h e space v a l u e space o f space g equals 9.8 space bevelled m over s squared space comma space t h e space p l a n e t space c o u l d space b e space e a r t h$

Suggest Corrections

Similar questions

(a) Is the acceleration due to gravity of earth 'g' a constant? Discuss.
(b) Calculate the acceleration due to gravity on the surface of a satellite having a mass of $7.4 \times 10^{22}$ kg and a radius of $1.74 \times 10^{6} m (G = 6.7 \times 10^{- 11} N m^{2} / k g^{2})$ . Which satellite do you think it could be?

Q. Calculate the force of gravitation due to earth on a ball of

1 k g

mass lying on the ground.(Mass of earth

= 6 \times 10^{3} k m

; and

G = 6.7 \times 10^{- 11} N m^{2} / k g^{2})

The mass and diameter of a planet have twice the value of the corresponding parameters of earth.
Acceleration due to gravity on the surface of the planet is

Q. A spaceship orbits around a planet at a height of 20 km from its surface. Assuming that only gravitational field of the planet acts on the spaceship, what will be the number of complete revolutions made by the spaceship in 24 hours around the planet ?
[Given : Mass of planet =

8 \times 10^{22} k g

;
Radius of planet =

2 \times 10^{6} m

,
Gravitational constant

G = 6.67 \times 10^{- 11} N m^{2} / k g^{2}

]

Q. A planet has twice the mass of earth and of identical size. What will be the height above the surface of the planet where its acceleration due to gravity reduces by

36

of its value on its surface?

Join BYJU'S Learning Program

The mass of a planet is 6×1024 kg and its diameter is 12.8×103 km. If the value of gravitational constant be 6.7×10−11Nm2/kg2, calculate the value of acceleration due to gravity on the surface of the planet. What planet could this be ?

Acceleration due to gravity,

The mass of a planet is $6 \times 10^{24}$ kg and its diameter is $12.8 \times 10^{3}$ km. If the value of gravitational constant be $6.7 \times 10^{- 11} N m^{2} / k g^{2}$ , calculate the value of acceleration due to gravity on the surface of the planet. What planet could this be ?