The mass of an electron is 9-1- 10 -31 kg- If its kinetic energy is 3-0- 10 -25 J- calculate its wave length-

λ = h / (2mK.E)^1/2 λ = 6.626× 10^ 34 / (2× 9.1× 10^ 31× 3× 10^ 25 )^1/2 #160; = 1.2 × 10^ 7m ...

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Standard XII

Chemistry

1900's Physics and Wave

The mass of a...

Question

The mass of an electron is $9.1 \times 10^{- 31}$ kg. If its kinetic energy is $3.0 \times 10^{- 25}$ J, calculate its wave length.

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Solution

$λ = h / (2 m K . E)^{1 / 2}$
$λ = 6.626 \times 10^{- 34} / (2 \times 9.1 \times 10^{- 31} \times 3 \times 10^{- 25})^{1 / 2} = 1.2 \times 10^{- 7} m$

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The mass of an electron is 9.1×10−31 kg. If its kinetic energy is 3.0×10−25 J, calculate its wave length.

λ=h/(2mK.E)1/2λ=6.626×10−34/(2×9.1×10−31×3×10−25)1/2=1.2×10−7m

The mass of an electron is $9.1 \times 10^{- 31}$ kg. If its kinetic energy is $3.0 \times 10^{- 25}$ J, calculate its wave length.

$λ = h / (2 m K . E)^{1 / 2}$
$λ = 6.626 \times 10^{- 34} / (2 \times 9.1 \times 10^{- 31} \times 3 \times 10^{- 25})^{1 / 2} = 1.2 \times 10^{- 7} m$