Question

The mass of an iron rod is $52g$. The density of iron is $7.8gc{m}^{-3}$. Find the volume of the rod.

Answer 1

Step-1: Given

Mass of the iron rod, $m=52g$

Density of iron rod, $\rho =7.8gc{m}^{-3}$

Step-2: Formula

$Density\left(\rho \right)=\frac{mass\left(m\right)}{volume\left(V\right)}$

Step-3: Volume of iron rod will be

$$\begin{gathered} Density\left(\rho \right)=\frac{mass\left(m\right)}{volume\left(V\right)} \\ \Rightarrow volume\left(V\right)=\frac{mass\left(m\right)}{Density\left(\rho \right)} \\ \Rightarrow volume\left(V\right)=\frac{52g}{7.8g.c{m}^{-3}} \\ \Rightarrow volume\left(V\right)=6.7c{m}^3 \end{gathered}$$

Hence, the volume of rod is $\left(V\right)=6.7c{m}^3$