Question

The mass of $CaC{O}_3$ is required to react with $25mL$ of $0.75MHCl$ is :

• A. $0.94g$
• B. $9.4g$
• C. $0.094g$
• D. $0.098g$

Answer 1

The correct option is A $0.94g$

The1000mL of $HCl$=27.375g then the 1 ml of solution contains HCl

$\frac{27.375}{1000\times 1}$

25ml of solution which contains $HCl$$=\frac{27.375}{1000\times 25}=0.684g$

The chemical equation can be given as:

${CaCO}_{3\left(s\right)}+2HCl\to {CaCl}_2+{CO}_2+H_{2}O$

2mol of HCl reacts with 1 mol of ${CaCO}_3$

The amont of ${CaCO}_3$ reacted is given by,

$\frac{100}{71}\times 0.684g=0.9639g$$\approx 0.94g$