Question

The mass of lime $\left(CaO\right)$ (in kg as the nearest integer) obtained by heating $200$ $kg$ of $95\%$ pure limestone $\left(Ca{CO}_3\right)$ is:

Answer 1

Given, mass of pure lime stone in $200$ kg sample $=$ $\frac{(95\times 200)}{100}$ $=$ $190$ kg.

Now, $Ca{CO}_3\to CaO+C{O}_2$

$100$ $56$ $44$ (Molecular mass)

$\therefore 100$ $kg$ $Ca{CO}_3\equiv 56kg$ $CaO$

$\therefore 190$ $kg$ $Ca{CO}_3\equiv \frac{56\times 190}{100}=106.4$ $kg$ $CaO$.

So, nearest integer value is $106$.