Question

The mass of oxalic acid (hydrated) required to prepare $500$ mL of its $0.1N$ solution is :

• A. $0.315$ g
• B. $6.3$ g
• C. $3.15$ g
• D. $63.0$ g

Answer 1

The correct option is C $3.15$ g

For hydrated oxalic acid, $(COOH{)}_2.2H_{2}O$, molar mass is $126$ g/mol.
Equivalent weight $=\frac{M}{2}=63$
Meq. of oxalic acid $=500\times 0.1=50$
$\frac{w}{E\times 1000}=50$
$w=\frac{126}{2}\times 50\times 1000=3.15$ g

Hence, mass of oxalic acid required is $3.15$ g.