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Stoichiometry

The mass of o...

Question

The mass of oxygen present in $0.5$ mole of $P_{4} O_{10}$ is:
(atomic weight $P = 31, O = 16$ )

160

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80

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240

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124

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Solution

The correct option is B $80$ g
Mass of oxygen present in $1$ mole of $P_{4} O_{10}$
$16 \times 10 = 160 g m$
Similarly,
For $0.5$ moles of $P_{4} O_{10}$
$\frac{160}{2} = 80 g m$

Suggest Corrections

Similar questions

The mass of 0.5 moles of Water molecules is:

(Atomic mass, H =1; O = 16)

H_{3} P O_{4}

P_{4}

P_{4} + O_{2} ⟶ P_{4} O_{10}

P_{4} O_{10} + H_{2} O ⟶ H_{3} P O_{4}

N a_{2} C_{2} O_{4}

6.7

C = 12, O = 16, N a = 23

[N a O H]

160

N a = 23, O = 16, H = 1

16 g

O

1 m o l e

1

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