The mass of oxygen that would be required to produce enough $C O$ , which completely reduces $1.6 k g F e_{2} O_{3}$ (at. mass $F e = 56$ ) is____________.

240 g m

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480 g m

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720 g m

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960 g m

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Solution

The correct option is B $480 g m$
$C + \frac{1}{2} O_{2} ⟶ C O$
$F e_{2} O_{3} + 3 C O ⟶ 2 F e + 3 C O_{2}$
160 g of $F e_{2} O_{3}$ needs 84g of $C O$
1.6 kg of $F e_{2} O_{3}$ needs $= \frac{84}{160} \times 1.6 \times 10^{3}$
$= 840 k g$
For 28 g of CO formation amount of oxygen needed $= 16 g$
For 840 g of CO formation amount of oxygen needed $= \frac{16}{28} \times 840$
$= 480 g$

Suggest Corrections

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