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Question

The mass of P4O10 produced, if 440 g of P4S3 is mixed with 384 gm of O2, is:


P4S3+O2P4O10+SO2

A
568 gm
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B
426 gm
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C
284 gm
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D
396 gm
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Solution

The correct option is C 568 gm
The balanced chemical equation is P4S3+8O2P4O10+3SO2.

The molar masses of P4S3, O2 and P4O10 are 220 g/ mol, 32 g/mol and 283.9 g/mol, respectively.

The number of moles of P4S3 and O2 are 440220=2 and 38432=12, respectively.

1 mol of P4S3 reacts with 8 moles of O2. So, 2 mol of P4S3 reacts with 16 moles of O2.

Thus, P4S3 is the limiting reagent since there is only 12 moles of O2.

1 moles of P4S3 will react with 8 moles of oxygen to form 1 moles of P4O10.

The mass of P4O10 produced is 12×2848=426 g.

Hence, the correct option is B.

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