Question

The mass of a ball in air is $48g$. It is immersed in water contained in a measuring cylinder. The water level rises by $20c{m}^3$ when the ball is completely submerged. What is the density of the ball?

A. $4.8gc{m}^{-3}$
B. $0.42gc{m}^{-3}$
C. $2.0gc{m}^{-3}$
D. $2.4gc{m}^{-3}$

• A. $4.8g/c{m}^3$
• B. $2.4g/c{m}^3$
• C. $2.0g/c{m}^3$
• D. $0.42g/c{m}^3$

Answer 1

The correct option is D. $2.4gc{m}^{-3}$.

Given,

Mass of the ball in the air $=48g$

Volume of the displaced liquid $=20c{m}^3$

We know that,
$\frac{\text{Density of object}}{\text{Density of liquid}}=\frac{\text{Weight of the Object}}{\text{Weight of the displaced liquid}}$
$⟹\frac{\text{Density of object}}{1gc{m}^{-3}}=\frac{48g}{20g}$
$⟹\text{Density of object}=2.4gc{m}^{-3}$