The mass percentage of nitrogen in urea ( $N H_{2} C O N H_{2}$ ) is .

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Solution

The correct option is B 47
Molecular mass of urea ( $N H_{2} C O N H_{2}$ )
$= 2 \times$ Atomic mass of $N$ + $4 \times$ Atomic mass of $H$ + Atomic mass of $C$ + Atomic mass of $O = 60$

Mass percentage of nitrogen $= \frac{Mass of an element}{Mass of compound} \times 100 = 46.67 %$

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