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Standard XII

Physics

Acceleration

The masses of...

Question

The masses of 10 kg and 20 kg respectively are connected by a massless spring. A force of 200 N acts on the 20 kg mass. At the instant shown, the 10 kg mass has an acceleration of $12 m s^{- 2}$ , what is the acceleration of 20 kg mass?

12 m s^{- 2}

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4 m s^{- 2}

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10 m s^{- 2}

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none of these

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Solution

The correct option is B $4 m s^{- 2}$
When the 10Kg mass has an acc. of $12 m / {s e c}^{2}$
Then the spring force acting on the body will be $= k x = 10 \times 12 = 120 N$
Now, let the acc. of mass 20Kg $=^{'} a^{'}$
So, the equation of motion for 20Kg body is,
$200 - k x = 20 \times a \Rightarrow 20 a = 200 - 120 = 80 \Rightarrow a = 80 / 20 = 4 m / {s e c}^{2}$

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The masses of 10 kg and 20 kg respectively are connected by a massless spring. A force of 200 N acts on the 20 kg mass. At the instant shown, the 10 kg mass has an acceleration of 12ms−2, what is the acceleration of 20 kg mass?

The correct option is B 4ms−2When the 10Kg mass has an acc. of 12m/sec2Then the spring force acting on the body will be =kx=10×12=120NNow, let the acc. of mass 20Kg =′a′So, the equation of motion for 20Kg body is,200−kx=20×a⇒20a=200−120=80⇒a=80/20=4m/sec2

The masses of 10 kg and 20 kg respectively are connected by a massless spring. A force of 200 N acts on the 20 kg mass. At the instant shown, the 10 kg mass has an acceleration of $12 m s^{- 2}$ , what is the acceleration of 20 kg mass?