Question

# The masses of neutron and proton are 1.0087 and 1.0073 amu respectively. If the neutrons and protons combine to form helium nucleus of mass 4.0015 amu the binding energy of the helium nucleus will be

A
28.4 MeV
B
20.8 MeV
C
27.3 MeV
D
14.2 MeV

Solution

## The correct option is C 28.4 MeVTotal protron in helium is 2 and neutron in helium is 2 mass defect $$\Delta M=2(1.0087+1.0073)-4.0015=0.0305 amu$$Binding energy $$E=931\Delta M=28.4MeV$$Physics

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