The masses of neutron and proton are 1.0087 and 1.0073 amu respectively. If the neutrons and protons combine to form helium nucleus of mass 4.0015 amu the binding energy of the helium nucleus will be

28.4 MeV

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20.8 MeV

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27.3 MeV

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14.2 MeV

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Solution

The correct option is C 28.4 MeV
Total protron in helium is 2 and neutron in helium is 2
mass defect $Δ M = 2 (1.0087 + 1.0073) - 4.0015 = 0.0305 a m u$
Binding energy $E = 931 Δ M = 28.4 M e V$

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Similar questions

Q. The masses of neutron and proton are 1.0087 amu and 1.0073 amu respectively. If the neutrons and protons combine to form a helium nucleus (alpha particles) of mass 4.0015 amu. The binding energy of the helium nucleus will be [1 amu= 931 MeV]

The masses of neutron and proton are 1.0087 amu and 1.0073 amu respectively. If the neutrons and protons combine to form a helium nucleus (alpha particles) of mass 4.0015 amu, the binding energy of the helium nucleus will be [1 amu= 931 MeV]

Q. The masses of neutron and proton are

1.0087 a . m . u .

and

1.0073 a . m . u .

respectively. If the neutrons and protons combine to form a helium nucleus (alpha particles) of mass

4.0015 a . m . u

, then the binding energy fo the helium nucleus will be: (

1 a . m . u . = 931 M e V

)

Q. The binding energy of an

α

-particle is
(Given that mass of proton

=

1.0073

amu, mass of neutron

=

1.0087

amu, and mass of

α

-particle

=

4.0015

amu)

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The masses of neutron and proton are 1.0087 and 1.0073 amu respectively. If the neutrons and protons combine to form helium nucleus of mass 4.0015 amu the binding energy of the helium nucleus will be

The correct option is C 28.4 MeVTotal protron in helium is 2 and neutron in helium is 2 mass defect ΔM=2(1.0087+1.0073)−4.0015=0.0305amuBinding energy E=931ΔM=28.4MeV

The correct option is C 28.4 MeV
Total protron in helium is 2 and neutron in helium is 2
mass defect $Δ M = 2 (1.0087 + 1.0073) - 4.0015 = 0.0305 a m u$
Binding energy $E = 931 Δ M = 28.4 M e V$