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The maximum amplitude of an A.M. wave is found to be $15 V$ while Its minimum amplitude is found to be $3 V$ . What Is the modulation Index?

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Solution

$A_{c} + A_{m} = 15$ and $A_{c} - A_{m} = 3$
$2 A_{c} = 18, 2 A_{m} = 12$
$m = \frac{A_{m}}{A_{c}} = \frac{6}{9} = \frac{2}{3}$

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