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Amplitude of a Wave

The maximum a...

Question

The maximum amplitude of an AM wave is found to be 15 V while its minimum amplitude is found to be 3 V. the modulation index is

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Solution

The correct option is B
2 / 3

$A_{c} + A_{m} = 15$

$A_{c} - A_{m} = 3$

Solving $A_{c} = 9, A_{m} = 6$

Modulation index, $m = \frac{A_{m}}{A_{c}} = \frac{6}{9} = \frac{2}{3}$

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