Question

The maximum and minimum amplitude of an AM wave are 150mV and 50mV respectively. The depth of modulation is

• A. 0.02
• B. 0.7
• C. 0.5
• D. 1

Answer 1

Answer: (C)

0.5

Depth of modulation is given by: $m=\frac{A_{max}-A_{min}}{A_{max}+A_{min}}$
where $A_{max}$ is the maximum amplitude of the AM wave and $A_{min}$ is the minimum amplitude of the AM wave
Thus, $m=\frac{150-50}{150+50}=0.5$