Question

The maximum and minimum resultant capacity that can be obtained with $2\mu F,3\mu F$ and $6\mu F$ are respectively:

• A. $11\mu F,1\mu F$
• B. $11\mu F,6\mu F$
• C. $11\mu F,2\mu F$
• D. $11\mu F,4\mu F$

Answer 1

The correct option is A $11\mu F,1\mu F$

Maximum capacitors is obtained when they are connected in parallel
$C_{eff}=C_1+C_2+C_3$
$C_{max}=2+3+6$
$C_{max}=11\mu F$
Minimum capacitance occurs when capacitors are connected in series. So:
$\frac{1}{C_{min}}=\frac{1}{2}+\frac{1}{3}+\frac{1}{6}$
or, $C_{min}=1\mu F$