Question

The maximum baggage weight allowed on the ferry is 9 lb. The laptop weighs 5/3 lb and bag itself weighs is 3/2lb. What is the maximum amount of tea ($x$) that can be carried on the ferry?

• A. $x$ + 5/3 < 19/6
• B. $x$ < 35/3
• C. $x$ > 35/2
• D. $x$ < 35/6

Answer 1

The correct option is D $x$ < 35/6

The maximum weight of tea that can be carried is $x$ lb.
Weight of laptop = $\frac{5}{3}$ lb
Weight of bag itself = $\frac{3}{2}$ lb
Maximum allowed weight = 9 lb

So, the ineqality that we get is,
$x$ + $\frac{5}{3}$ + $\frac{3}{2}$ < 9
$\Rightarrow$ $x$ + $\frac{10+9}{6}$ < 9
$\Rightarrow$ $x$ + $\frac{19}{6}$ < 9
$\Rightarrow$ $x$ + $\frac{19}{6}$ - $\frac{19}{6}$ < 9 - $\frac{19}{6}$
$\Rightarrow$ $x$ < $\frac{35}{6}$ lb