Question

The maximum weight a bag can hold is 7 lb. If the weight of clothes is 5/2 lb and food is 2 lb, the maximum weight of tea that can be carried is .

• A. 2 lb
• B. 3/2 lb
• C. 5/2 lb
• D. 7/2 lb

Answer 1

The correct option is C 5/2 lb

Let the weight of tea that can be carried be $z$ lb.
Weight of clothes = $\frac{5}{2}$ lb
Weight of food = 2 lb
Total weight that the bag can hold = 7 lb

So the ineqality we get is,

$z$ + $\frac{5}{2}$ + 2 $\le$ 7
$\Rightarrow$ $z$ + $\frac{9}{2}$ $\le$ 7
$\Rightarrow$ $z$ + $\frac{9}{2}$ - $\frac{9}{2}$ $\le$ 7 - $\frac{9}{2}$
$\Rightarrow$ $z$ $\le$ $\frac{14-9}{2}$
$\Rightarrow$ $z$ $\le$ $\frac{5}{2}$ lb

$\therefore$ The maximum weight of tea that can be carried is $\frac{5}{2}$ lb.