Question

The maximum current in the circuit is given as $\frac{x}{1000}mA$. Find $x$.

Answer 1

$\omega =\frac{2}{\sqrt{LC}}=\frac{2}{\sqrt{5\times {10}^{-3}\times 20\times {10}^{-6}}}$
$=6324.5rad/s$
$X_L=\omega L=\left(6324.5\right)(5\times {10}^{-3})=31.62\Omega$
$X_C=\frac{1}{\omega C}=\frac{1}{6324.5\times 20\times {10}^{-6}}=7.9\Omega$
$\therefore Z=X_L-X_C=23.72\Omega$
$i_0=\frac{V_0}{Z}=\frac{5}{23.72}mA=0.211mA$.