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Standard VIII

Biology

Method of finding LCM

The maximum e...

Question

The maximum energy $K_{m a x}$ of photoelectrons emitted in a photoelectric cell is measured using lights of various frequencies $v$ . The given graph shows how $K_{m a x}$ varies with $v$ . The slope of the graph is equal to

the charge of an electron

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the charge to mass ratio of an electron

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the work function of the emitter in the cell

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Planck's constant.

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Solution

The correct option is D Planck's constant.
We know that, $K_{m a x} = e V_{0} = h (v - v_{0})$
This is a straight line with slope equal to $h$ , i.e., the Planck's cosntant. Hence, the correct choice is (d).

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Similar questions

Q. The maximum energy

K_{m a x}

of photoelectrons emitted in a photoelectric cell is measured using lights of various frequencies

v

. The given graph shows how

K_{m a x}

varies with

v

. The slope of the graph is equal to

Q. The ratio of slopes of

K_{m a x}

vs.

ν

and

V_{0}

ν

curves in the photoelectric effect gives (v =frequency,

K_{m a x}

= maximum kinetic energy,

v_{0}

= stopping potential):

Q. The ratio of slopes of

K_{m a x} v s ν

and

V_{0} v s ν

curves in the photoelectric effect gives:

(ν

= frequency,

K_{m a x}

= maximum kinetic energy,

V_{0}

= stopping potential)

Q. The maximum kinetic energy

(E_{m a x})

of photoelectrons emitted in a photoelectric cell varies with frequency (

v

) as shown in the graph. The slope of the graph is equal to

When a high frequency electromagnetic radiation is incident on a metallic surface, electrons are emitted from the surface. Energy of emitted photoelectrons depends only on the frequency of incident electromagnetic radiation and the number of emitted electrons depends only on the intensity of incident light.

Einstein's photoelectric equation

[K_{m a x} = h ν - ϕ]

correctly explains the PE, where

ν =

frequency of incident light and

ϕ =

work function.

The slope of the graph shown in fig. [here h is the Planck's constant and e is the charge of an electron] is

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The maximum energy Kmax of photoelectrons emitted in a photoelectric cell is measured using lights of various frequencies v. The given graph shows how Kmax varies with v. The slope of the graph is equal to

The correct option is D Planck's constant.We know that, Kmax=eV0=h(v−v0) This is a straight line with slope equal to h, i.e., the Planck's cosntant. Hence, the correct choice is (d).

The maximum energy $K_{m a x}$ of photoelectrons emitted in a photoelectric cell is measured using lights of various frequencies $v$ . The given graph shows how $K_{m a x}$ varies with $v$ . The slope of the graph is equal to

The correct option is D Planck's constant.
We know that, $K_{m a x} = e V_{0} = h (v - v_{0})$
This is a straight line with slope equal to $h$ , i.e., the Planck's cosntant. Hence, the correct choice is (d).