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Question

The maximum height reached by the projectile is 4 m. The horizontal range is 12 m. Velocity of projection (in ms1) is
(g is acceleration due to gravity)

A
5g2
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B
3g2
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C
13g2
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D
15g2
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Solution

The correct option is A 5g2
In a projectile projected at angle θ maximum height and range is given by
Hmax=u2sin2θ2g=4.....(i)Rmax=u2sin2θg=12......(ii)
Dividing equation (ii) by equation (i)
3=sin2θsin2θ×232=2sinθcosθsin2θtanθ=43
sinθ=45Using equation (i) 4=u22g×(45)2u2=25g2u=5g2 m/s

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