Question

The maximum number of stereoisomers possible for the ion $\left[\stackrel{IV}{Pd}\right(N{H}_3{)}_2(H_{2}O{)}_{2}B{r}_2{]}^{2+}$ is :

Answer 1

Six stereoisomers (optical and geometrical) are possible for $\left[\stackrel{IV}{Pd}\right(N{H}_3{)}_2(H_{2}O{)}_{2}B{r}_2{]}^{2+}$.

They are as follows:
(1) to (5) are geometrical isomers; (5) and (6) are optical isomers.