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Question

The maximum of 4sin2x+3cos2x is

A
4
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B
3
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C
7
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D
5
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Solution

The correct option is A 4
4sin2x+3cos2x=4sin2x+33sin2x=3+sin2x
Thus, the maximum value of the expression becomes 4 since the maximum value of sin2x is 1.

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