Question

The maximum peak to peak voltage of an $AM$ wave is $24mV$ and the minimum peak to peak voltage is $8mV$, then the modulation factor $\left(m_a\right)$ is

• A. $50$%
• B. $75$%
• C. $25$%
• D. $10$%

Answer 1

The correct option is A $50$%

Given, $V_{max}=\frac{24}{2}=12mV$
and $V_{min}=\frac{8}{2}=4mV$
$m_a=\frac{V_{max}-V_{min}}{V_{max}+V_{min}}=\frac{12-4}{12+4}=\frac{8}{16}=\frac{1}{2}$
$=0.5=50$%.