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Question

The maximum speed and acceleration of a particle executing simple harmonic motion are 10cms1 and 50cms2. Find the position(s) of the particle when the speed is 8cm1.


A

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B

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C

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D

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Solution

The correct option is B


Max speed

v=Aω=10 ...(1)

max acceleration

a=Aω2=50 ...(ii)

Dividing (ii) with (i)

ω=5 ...(iii)

substituting (iii) in (i)

10=A×5

A=2 ...(iv)
We derived the relation between v and x as.

v=ωA2x2

To find x when v = 8

8=54x2

x2=46425x=3625=±65=±1.2cm


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